Difference between revisions of "Cubic Polynomial"

From alpha
Jump to navigation Jump to search
(Created page with "A cubic polynomial is a type of polynomial with the highest power of the variable or degree to be <math>3</math>. Cubic polynomials are used in various areas of mathematics an...")
 
Line 7: Line 7:


<math>4x^3</math> , <math>2x^3+1</math> , <math>5x^3+x^2</math> , <math>2x^3+4x^2+6x+7</math>
<math>4x^3</math> , <math>2x^3+1</math> , <math>5x^3+x^2</math> , <math>2x^3+4x^2+6x+7</math>
== Example ==
Factorise  <math>x^3-23x^2+142x-120</math>
<math>x^3-23x^2+142x-120</math>
<math>x^3-x^2-22x^2+22x+120x-120</math>
<math>x^2(x-1)-22x(x-1)+120(x-1)</math>
<math>(x-1)(x^2-22x+120)</math>  Taking <math>(x-1)</math> common
Now factorise <math>x^2-22x+120</math>
<math>x^2-22x+120</math>
<math>x^2-10x-12x+120</math>
<math>x(x-10)-12(x-10)</math>
<math>(x-10)(x-12)</math>
<math>x^3-23x^2+142x-120=(x-1)(x-10)(x-12)</math>
Solution : Let p(x) = x 3 – 23x 2 + 142x – 120 We shall now look for all the factors of –120. Some of these are ±1, ±2, ±3, ±4, ±5, ±6, ±8, ±10, ±12, ±15, ±20, ±24, ±30, ±60. By trial, we find that p(1) = 0. So x – 1 is a factor of p(x). Now we see that x 3 – 23x 2 + 142x – 120 = x 3 – x 2 – 22x 2 + 22x + 120x – 120 = x 2 (x –1) – 22x(x – 1) + 120(x – 1) (Why?) = (x – 1) (x 2 – 22x + 120) [Taking (x – 1) common] We could have also got this by dividing p(x) by x – 1. Now x 2 – 22x + 120 can be factorised either by splitting the middle term or by using the Factor theorem. By splitting the middle term, we have: x 2 – 22x + 120 = x 2 – 12x – 10x + 120 = x(x – 12) – 10(x – 12) = (x – 12) (x – 10) So, x 3 – 23x 2 – 142x – 120 = (x – 1)(x – 10)(x – 12)

Revision as of 08:48, 11 May 2024

A cubic polynomial is a type of polynomial with the highest power of the variable or degree to be . Cubic polynomials are used in various areas of mathematics and science, including physics, engineering, and economics.

Definition

A cubic polynomial is a polynomial with the highest exponent of a variable i.e. degree of a variable as . The general form of a cubic polynomial is , , where are coefficients and is the constant with all of them being real numbers. An equation involving a cubic polynomial is called a cubic equation.

Some of the examples of a cubic polynomial are

, , ,

Example

Factorise

Taking common

Now factorise






Solution : Let p(x) = x 3 – 23x 2 + 142x – 120 We shall now look for all the factors of –120. Some of these are ±1, ±2, ±3, ±4, ±5, ±6, ±8, ±10, ±12, ±15, ±20, ±24, ±30, ±60. By trial, we find that p(1) = 0. So x – 1 is a factor of p(x). Now we see that x 3 – 23x 2 + 142x – 120 = x 3 – x 2 – 22x 2 + 22x + 120x – 120 = x 2 (x –1) – 22x(x – 1) + 120(x – 1) (Why?) = (x – 1) (x 2 – 22x + 120) [Taking (x – 1) common] We could have also got this by dividing p(x) by x – 1. Now x 2 – 22x + 120 can be factorised either by splitting the middle term or by using the Factor theorem. By splitting the middle term, we have: x 2 – 22x + 120 = x 2 – 12x – 10x + 120 = x(x – 12) – 10(x – 12) = (x – 12) (x – 10) So, x 3 – 23x 2 – 142x – 120 = (x – 1)(x – 10)(x – 12)